Question

two identical charges of magnitude Q are placed at distance r from each other another another charge q is placed at mid point on the line joining than two charges find the magnitude and nature of the charged particle​

Answer 1

Answer:

q= -Q/4 will be the ans. as

Acc to question

force of first on second

F= KQ²/r²

and force by second charge on first will be equal but in opposite direction. and as we positive charge will repel each other. so we need to put a negative charge at centre to make system in Equilibrium. so,

KQ²/r²= - Kq²/(r/2)²

=KQ²/r² = - 4Kq²/4

on solving the equation we will get

q = Q/4

and sign will be negative

Thank You