Question

two identical containers connected by a fine capillary tube contain air at N.T.P.if one of those containers is immersed in pure water , boiling under normal pressure then new pressure is​

Answer 1

Answer:

Since the number of moles of gas in the system remains constant:

Moles in first container earlier+Moles in second container earlier=Moles in first container later+Moles in second container later

P0 V / RT0. + P0V / RT0 = P1V / RT0 + P1V / RT1

T0 =273 K

,T1 =373 K,

P0 =76 cm of Hg

so

P1 = =87.76 cm of Hg