Two identical copper spheres are separated by 1m in vaccum How many electrons would have to be removed from one sphere and added to the other so that they now attract each other with a force of 0.9N
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Answered by
108
Let the charge on the sphere from which e⁻ are being removed be +q and to which they are being added be -q
Therefore, Force exerted by one sphere on other would be
F = Kq₁q₂/r² where K= 9*10⁹ Nm²C⁻²
It is given that, F = 0.9N
Therefore, 0.9 = -9*10⁹q²/(1)²
=> q = 10⁻⁵ C
But q=ne, where n is the number of charged particles (e⁻ here),
and e = 1.6*10⁻¹⁹ C
Solving, number of electrons = 6.25*10¹³
Therefore, Force exerted by one sphere on other would be
F = Kq₁q₂/r² where K= 9*10⁹ Nm²C⁻²
It is given that, F = 0.9N
Therefore, 0.9 = -9*10⁹q²/(1)²
=> q = 10⁻⁵ C
But q=ne, where n is the number of charged particles (e⁻ here),
and e = 1.6*10⁻¹⁹ C
Solving, number of electrons = 6.25*10¹³
Answered by
26
Answer:
6.25×10power15
Explanation:
GivenF=o.9N , r=1m.
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