Question

Two identical discs are moving with the same kinetic Energy. One of them rolls and the other slides. Which one moves faster? *

The disc that rolls
The disc that slides
Both have same velocity
Both travels same distance​

Answer 1

The disc that slides

Explanation:

Let

$V_{A}$ be the disc that rolls &

$V_{B}$ be the disc that slides

Kinetic energy is equal for both     (given)

so,

$\frac{1}{2}$ Iω^2 + $\frac{1}{2}$ M$V_{A}$^2 = $\frac{1}{2}$ M$V_{B}$^2

From here,

Moment of energy of the disc,

⇒ $\frac{1}{2}$ $\frac{MR^2 }{2}$ * $\frac{V_{A} ^2}{R^2} + \frac{1}{2} MV_{A}^2$ = $\frac{1}{2}$ M$V_{B}$^2

⇒ $3V_{A}^{2} = 2V_{B}^{2}$

∵ $\frac{V_{A}}{V_{B}}$ = $\sqrt{\frac{2}{3} }$

Thus, $V_{B}$ or the disc that slides moves faster with the velocity of $\sqrt{3}$.

Learn more: Kinetic Energy

brainly.in/question/11384416

Answer 2

Answer:

root 2:root 3is the

I hope it will use for u