Question

Two identical metallic balls with equal charges are kept 4.5cm apart. The force between both the balls increases by 10%on giving extra charge of 0.001mc to one of the ball. Calculate the charge on each ball

Answer 1

Answer:

-1/9coloumb

Explanation:

we have distance between the two charges is 4.5cm i.e. 0.045m

let the charge is q

now the force is between the two charges is kq²/(0.045)²

again from the question we have 10%force increases by adding 0.001mc=1c charge on either charge. sothat out of two charges one is q and another is q+1

so kq(q+1)/(0.045)²=kq²/(0.045)²(10/100)

=q²+q=q²/10

=9q²=-q

=q=-1/9c