Math, asked by shafaq40, 18 days ago

. Two identical metallic cubes of side 5cm are melted to form a solid cylinder of radius 7cm. What will be the height of the cylinder so formed? (use π=22/7)​

Answers

Answered by harshit5645
5

Answer:

Given:

Height (h) of cylindrical part = height (h) of the conical part =7 cm

Diameter of the cylindrical part =12 cm

Therefore, Radius (r) of the cylindrical part =

2

12

=6 cm

So, Radius of the conical part =6 cm

Slant height (l) of conical part =

r

2

+h

2

cm

=

6

2

+7

2

=

36+49

=

85

≈9.22 cm.

The total surface area of the remaining solid = CSA of the cylindrical part + CSA of the conical part + Base area of the circular part

=2πrh+πrl+πr

2

=2×

7

22

×6×7+

7

22

×6×9.22+

7

22

×6×6

=264+173.86+113.14

=551 cm

2

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