Question

two identical point charges q each are kept 2m apart in air. A third point charges Q of unknown magnitude and sign is placed on the line joining the charges such that the system remains in equilibrium. Find the position and nature of Q
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Answer 1

Answer:

At 1m

it will be in equilibrium either its +chg or -chg

Explanation:

Mark the answer brainliests please

Answer 2

Answer:

Explanation:

position of charge Q can be determined by equating the forces acting on Q due to the two charges q

kQq/$r^{2}$=kQq/$(2-r)^{2}$

r = 1 m

for the system to remain in equilibrium equate forces on charge q due to other charge q and Q

i.e, kQq/$r^{2}$=kqq/$2^{2}$

Q=q/4