Two identical resistor each of resistance 12 ohm are connected 1)in series 2)in parallel in turn to a battery of 6volts. Calculate the ratio of power consumed in combination of resistor in two cases
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for first case R=24
second case R=12
V=6v
p=v*v/r
v is same for both therefore p is directly proportional to (1/r)
p1/p2=r2/r1
=12/24
=1/2
second case R=12
V=6v
p=v*v/r
v is same for both therefore p is directly proportional to (1/r)
p1/p2=r2/r1
=12/24
=1/2
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