Two identical resistors each of resistance 20 ohm are connected in parallel. This combination, in turn, is connected to a 10 ohm resistor. The equvalent resistance
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since the two identical resistors are connected in parallel their equivalent resistance is (20×20) ÷(20+20)= .10.
therefore, 10+10= 20ohms
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9
Hey dear,
◆ Answer-
R' = 20 ohm.
◆ Explaination-
# Given-
R1 = R2 = 20 ohm
R3 = 10 ohm
# Solution-
R1 & R2 are connected in parallel.
Resultant resistance for parallel combination is given by -
1/R = 1/R1 + 1/R2
1/R = 1/20 + 1/20
1/R = 2/20
R = 10 ohm
This R and R3 are connected in series.
Equivalent resistance in series combination is given by -
R' = R + R3
R' = 10 + 10
R' = 20 ohm
Equivalent resistance of overall structure is 20 ohm.
Hope this helps you...
◆ Answer-
R' = 20 ohm.
◆ Explaination-
# Given-
R1 = R2 = 20 ohm
R3 = 10 ohm
# Solution-
R1 & R2 are connected in parallel.
Resultant resistance for parallel combination is given by -
1/R = 1/R1 + 1/R2
1/R = 1/20 + 1/20
1/R = 2/20
R = 10 ohm
This R and R3 are connected in series.
Equivalent resistance in series combination is given by -
R' = R + R3
R' = 10 + 10
R' = 20 ohm
Equivalent resistance of overall structure is 20 ohm.
Hope this helps you...
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