Math, asked by akshatnayakak, 1 month ago

Two identical taps can fill an empty tank in 5 hours 30 minutes. Find the time taken by 3 similar taps to fill the empty tank.

Answers

Answered by moulinath2012
0

Answer:

let one tap can fill the empty tank in t min. given that two such taps together can fill the empty tank in t/2 min. t/2=330, t= 660 min, three such taps together can fill the tank= 660/3=220 min= 3 hours 40 minutes

Answered by plazmaimmortal
0

Answer:

3 hours 40 minutes

Step-by-step explanation:

2 taps fill in 5 hours 30 minutes. let us make this hour and minutes in decimels : - 30 minutes is 1/2 an hour (60 minutes) and 1/2 can be expressed as 0.5 so 5 hours 30 minutes can be expressed as:-

5.5.

2 taps fill 5.5

3 taps will fill in ?

2*5.5/3 = time

11/3 = time

3.6666 = time

.6666 = 2/3

2/3 of an hour (60 * 2/3) = 40 minutes

so 3 taps can fill in 3 hours 40 minutes

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