Two identical thin bar magnets each of length l and pole strength m are placed right angle to each other,with north pole of one touching south pole of the other,then the magnetic moment of the system is
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The magnetic moment of the system is√2mL
2.given that there are two identical thin bar magnets of length L
3.both are placed at right angles and their pole strength is m.
4.consider north pole of above magnet has pole strength touches south pole of the other
5.now we can consider length of magnet as the distance of hypotenuse joining south pole of above and north pole of below.
which comes out to be√L²+L²=√2L
6.M=m*2L
=√2 ml
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