Question

Two infinitely long, parallel and straight conductors each carrying a current of 5 A are separated by a short
distance in air. If each conductor experiences a force of 10-4 Nm, find the distance between them.​

Answer 1

Answer:

Consider that magnetic field density at point P is zero due to current carrying conductors.

According to right hand palm rule No. 1, direction of magnetic field will be perpendicular to the plane of the paper

(1) Downward due to current flowing in conductor X.

(2) Upward due to current flowing in conductor Y.

Since at point P,B=0

B

1

=B

2

2π

μ

0

x

L

1

=

2π

μ

0

24−x

L

2

x

5

=

24−x

7

5(24−x)=7x

5×24=12x⇒x=10cm from conductor X.

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