Two insulated charged copper sphere a and b each having charge of 6.5 x 10-7c are separated by a distance 50 cm. If they are placed in water of dielectric constant 80, then electrostatic force of repulsion between them is
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Answer:
F=1.68×10^-15
Explanation:
F=QxQ/4πE×r^2
F=(6.5)^2 x 10^-14/4xπx80x2500x10^-4
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