Two insulated charged copper spheres A and B have their centres
spo separated by
a distance
50 cm.
What is the mutual
force of
electrostatic repulsion if
the charge
each is 6.5× 10^-7C ? The radii
of A and B cre negligible
compared to the distance
of separation
Answers
Answered by
3
Answer:. 0.015N
Explanation:
By coloumbs law
F=kq1q2/r^2
F=(9×10^9×(6.5×10^-7)^2/(50×10^-2)^2
F=0.015N
Pls mark it as brainliest
Similar questions