Question

two interior angles of a ∆abc are <a = 75° and <b= 35° calculate <c and exterior angles of<a,<b,<c​

Answer 1

Answer:

let the exterior angle of a be x

let the exterior angle of b be y

let the exterior angle of c be z

by angle sum property

a+b+c=180°

75° + 35° + c = 180°

110° +c=180°

c = 180°- 110°

c = 70°

exterior angle of c

z+ 70°=180°(linear pair )

z =180°-70°

z =110°

exterior angle of b

y+35°=180°(linear pair)

y= 180°-35°

y =145°

exterior angle of a

x+75°=180°(linear pair)

x= 180°-75°

x=105°

Step-by-step explanation:

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Answer 2

Answer:

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