Question

Two interior angles of a triangle ABC traingle A =75° traingle B = 35°b calculate traingle C and exterior angles of traingle A ,B,C


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Answer 1

Step-by-step explanation:

Interior angle:

Sum of all angle =180°

A+B+C= 180°

75°+35°+C= 180°

110°+C=180°

180°-110°=70°

C=70°

Answer 2

Answer:

∠C = 70°

  (and)

  The exterior angles are 105°, 145°, 110°

Step-by-step explanation:

Given,

A = 75°

B = 35°

C = ?

Sum of all the interior angles of a triangle = 180°

⇒ A + B + C = 180°

⇒ 75° + 35° + x =180°  (Assume C as x)

⇒ x = 180°- 75° - 35°

⇒ x = 70°

∴ C = 70°

Let's find the exterior angles (see attachment 2)

Let the exterior angle of A be x

Let the exterior angle of B be y

Let the exterior angle of C be z

As we are aware of the formula,

exterior angle = sum of it's 2 opposite interior angles

→ x = 35° + 70°

⇒ x = 105°

→ y = 75° + 70°

⇒ y = 145°

→ z = 75° + 35°

⇒ z = 110°

∴∠C = 70°

  (and)

  The exterior angles are 105°, 145°, 110°

Hope it helps you❤❤❤