Math, asked by alvairis1995, 1 year ago

Two investments totaling $61,000 produce an annual income of $3240. One investment yields 9% per year, while the other yields 3% per year. How much is invested at each rate?


Anonymous: ___k off

Answers

Answered by manish5365
0

 \huge \bf\mathfrak \red{ANSWER:}

RS.23,500 AND RS. 37,500

\boxed{Step-by-step verification:}

Let, one investment be x and another be 61,000-x.

Then,

Income from first investment

= 9% of x

= 0.09x

Again,

Income from second investment

=3%of(61000−x)

=1830−0.03x

So,

Total income=I¹+I²

Or,

3240=0.09x+1830−0.03x

Or,

1410 = 0.06x

•°•

x = 23500x=23500

Again,

another investment

=61000−23500

=37500

So, the two investments are Rs. 23,500 and Rs. 37,500.


alvairis1995: can you answer my next question i posted please
alvairis1995: i just need the % answers only
alvairis1995: thank you
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