Two isoceles ∆ABC and ∆PQR have equal vertical angles and their areas are in the ratio 9:16 Find the ratio of their corresponding heights
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Answer:
3/4
Step-by-step explanation:
If two isosceles triangles have equal vertical angles then both triangles are similar.
So, △ABC∼△DEF
We know,
In similarity case
⇒Area of △ABCArea of △DEF
=(AB)2(DE)2 corresponding sides square
=(AM)2(DN)2 height
⇒916=(AM)2(DN)2
=916−−√= Ratio of their height
⇒ Ratio of height = 3 : 4
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