Question

Two ladders AB and PQ are resting against opposite walls of an alley. The ladders AB and PQ we 2m and 6m above the ground respectively and T is the point where the two ladders meet. Given that ∆TBP is similar to ∆TAQ, find an expression, in terms of y, for the length of PA​

Answer 1

Answer:

PA =4y

Step-by-step explanation:

given similarity x/6 = y/2

also NOTE ratio of Area : 1/2 .6 x/ 1/2 .2.y = 6x6/2x2

so

x=3y

so PA = x+y = 4y