Physics, asked by nikhilkrishna498, 1 year ago

two lamps are rated 100w ,220v

Answers

Answered by spagent000016
4

= (V*V)/R


1st lamp-


R1 =(V*V)/P


R1 = (220*220)/200 = 242 ohms


2nd lamp-


R2= (220*220)/100 = 484 ohms


Now, they are connected in series, so net resistance = 242+ 484 = 726 ohms


V= 220V


I= 220/726 = 0.303A


Power dissipated in first lamp, P1= (I*I)*R1 = (0.303*0.303)*242 = 22.222W


Power dissipated in 2nd lamp, P2= (I*I)*R2 = (0.303*0.303)*484 = 44.44 W


Power ratio, P1/P2 = 22.22/44.44 = 0.5


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