Two lamps one rate 80 w 220 v and the othee at 160 w 220 v are connecred in (1) in series(2) in parallel find the current in each case
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P = V^2/R'
R' = 220*220/80
R' = 605 ohm
R" = 220*220/160
R" = 302.5 ohm
in series
R = R' + R"
R = 605 + 302.5 = 907.5 ohm
in parallel
R =605*302.5/605+302.5
R = 201.6
Current in series
i' = 440/907.5 = 0.48 amp
Current in parallel
i" = 220/201.6 = 1.09Amp
Hope it helped you...
R' = 220*220/80
R' = 605 ohm
R" = 220*220/160
R" = 302.5 ohm
in series
R = R' + R"
R = 605 + 302.5 = 907.5 ohm
in parallel
R =605*302.5/605+302.5
R = 201.6
Current in series
i' = 440/907.5 = 0.48 amp
Current in parallel
i" = 220/201.6 = 1.09Amp
Hope it helped you...
8178026914avanishpat:
Thanks
Bhae apne 440 \ 907.5 kyu kara
220\907.5 nahe hona charge
qki series me voltage add kiya jata h aur parallel me voltage same rhta h
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