two lamps rated 100W, 220V and the other 60W, 220V are connected in parallel to electric mains supply.find the current drawn by two bulbs if the supply voltage is 220V?
Answers
Answer:
HI !
Power = P = 100 W
Voltage = V = 220v
Resistance = R
P = V²/R
100 = 220 ×220/R
R = 220 × 220/100
= 484 Ω
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Power = P = 60 W
Voltage = V = 220v
Resistance = R
P = V²/R
60 = 220 × 220/R
R = 220× 220/60
= 806.7 Ω
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As the resistors are connected in parallel ,
total resistance = 1/R
1/R = 1/484 + 1/806.7
= 806.7 + 484/484×806.7
= 1290.7/390442.8
R = 390442.8/ 1290.7 = 302.5 ohms
Total resistance = 302.5 Ω
I = current
V = IR
220 = I × 302.5
I = 220/302.5
= 0.73 A
The current drawn is 0.73 A
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Total current = 8/11 Ampere
Explanation:
The power of any appliance W = V I
here W is the power of lamp
V is the potential difference applied
I is the current flowing through the bulb .
Thus the current through first lamp I₁ = W/V = 100/220 Ampere
The current through second lamp I₂ = 60/220
Total current I = I₁ + I₂ = 100/220 + 60/220 = 160/220 = 8/11 Ampere