Question

Two large parallel conducting plates are 34 mm apart and carry equal but opposite charges on their
facing surfaces. An electron placed midway between the plates experiences a force of 3.2 × 10–16 N.
What is the potential difference (in volts) between the plates?

Answer 1

Explanation:

Given Two large parallel conducting plates are 34 mm apart and carry equal but opposite charges on their  facing surfaces. An electron placed midway between the plates experiences a force of 3.2 × 10–16 N.  What is the potential difference (in volts) between the plates?

• Now we need to potential difference V
• So d = 34 mm = 0.034 m
• Force F = 3.2 x 10^- 16 N
• So charge q = 1.6 x 10^-19 C.
• Now the magnitude of the electric field E = F / q
• Where F is electric force and q is the electric charge
• So E = 3.2 x 10^-16 / 1.6 x 10^- 19
• E = 2 x 10^3
• E = 2000 N / C
• Now we need to find the potential difference
• So V = E x d
• Or V = 2000 x 0.034
• Or V = 68 V

Reference link will be

https://brainly.in/question/8834286