two lenses of focal length is 8 cm and 4 cm are placed at a certain distance apart. calculate the distance between if the lenses is form a acromatic combination
Answers
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here's your answer
The combination of the focal length is 4 cm.
Explanation:
Given that,
Focal length f_{1} = 4\ cm
Focal length f_{1} = 4\ cm
Distance d = 8 cm
The combination of the focal length is defined as:
\dfrac{1}{f_{eq}}=\dfrac{1}{f_{1}}+\dfrac{1}{f_{2}}-\dfrac{d}{f_{1}f_{2}}
\dfrac{1}{f_{eq}}=\dfrac{1}{4}+\dfrac{1}{8}-\dfrac{4}{4\times8}
\dfrac{1}{f_{eq}}=\dfrac{1}{4}
f_{eq}=4\ cm
Given : Two lenses of focal length is 8 cm and 4 cm are placed at a certain distance apart.
To find : The distance between lenses if lenses is a form of acromatic combination.
solution : let distance between two lenses is d.
The condition for acromatic combination,
d = (f₁ + f₂)/2
where f₁ and f₂ are focal lengths of lenses.
here, f₁ = 8 cm , f₂ = 4cm
so, d = (8cm + 4cm)/2 = 6cm
Therefore distance between lenses is 6 cm.
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