Question

Two lenses of power for 3D and - 6D are placed in contact to form a composite lens an object is placed at a distance of 50 cm from the combination of lens find the position of image​

Answer 1

Answer:

v = -3.19

Explanation:

Given, u = -50 cm

Total Power of lens = (3 - 6)D = -3D

P = $\frac{1}{f}$ = -3

⇒ f = $-\frac{1}{3}$ m ------> (1)

$\frac{1}{f} = \frac{1}{v} - \frac{1}{u}$

⇒ $-\frac{1}{3}$ = $\frac{1}{v} - \frac{1}{50}$

⇒ $\frac{1}{v} = \frac{1}{50}-\frac{1}{3}$

⇒ $\frac{1}{v} = \frac{3-50}{150}$

⇒ $\frac{1}{v} = - \frac{150}{47}$ = -3.19 m