two line segments AC and BD intersect each other at the point P such that PA = 6 cm, PB = 3 cm, PC = 2.5 cm, PD = 5 cm, ∠APB = 50° and ∠ CDP = 30°. Then, ∠ PBA is equal to
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Answer:
30°
Step-by-step explanation:
In ΔABP and ΔCDP,
AP/BP = 6/3 = 2/1
DP/CP = 5/2.5 = 2/1
∠APB = ∠CPD
Hence they are proportional and similar.
So, ∠CDP = ∠PBA
∴ ∠PBA = 30°
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