two lines AB and CD intersect at a point O such that angle BOC + angle AOD=280 degree. find all the four angles
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140,40,140,40 will be the answer
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angle BOC+ANGLE AOD=280
LET BOC AND AOD =x
angle x+angle x =280
2x=280
x=140
for angle BOD,
180-140=40(ADJACENT ANGLES)
COA=BOD
=40(VERTICALLY OPPOSITE ANGLE)
LET BOC AND AOD =x
angle x+angle x =280
2x=280
x=140
for angle BOD,
180-140=40(ADJACENT ANGLES)
COA=BOD
=40(VERTICALLY OPPOSITE ANGLE)
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