Two lines AB and CD intersect at O.If angle Aoc=50°,Find angle AOD angle, BOD and angle BOC.
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angle AOC=50°
so angle DOB=50°[by Vertically opposite angle]
Now angle (AOC+COB)=180(by Linear pair)
so 50°+COB=180°
or COB=180°-50°
or COB=130°
Now angle COB =angle AOD(by Vertically opposite angle)
so angle AOD =130°
Hence angle AOD= 130°
COB=130°
&DOB=50°
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