Question

two liquid a and b are mixed ratio 1 ratio 2 and their vapour pressure of the solution is 24 store then two liquids are mixed in the reverse ratio of the vapour pressure of the solution increased by a fraction 1 ratio 4 the vapour pressure of pure a and b are respectively and give me answer ​

Answer 1

Answer:

Given, vapour pressure of benzene,

p

o

=640 mm Hg

Vapour pressure of solution,

p=600 mm Hg

Weight of solute, w=2−175g

Weight of benzene, W=39.08g

The molecular weight of benzene,

M=78g

The molecular weight of solute, m=?

According to Raoult's law

p

o

p

o

−p

=

m×W

w×M

640

640−600

=

m×39.08

2.175×78

640

40

=

m×39.08

2.175×78

m=

39.08

16×2.175×78

m=69.60

Hence, the correct option is C