two liquid a and b are mixed ratio 1 ratio 2 and their vapour pressure of the solution is 24 store then two liquids are mixed in the reverse ratio of the vapour pressure of the solution increased by a fraction 1 ratio 4 the vapour pressure of pure a and b are respectively and give me answer
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Answer:
Given, vapour pressure of benzene,
p
o
=640 mm Hg
Vapour pressure of solution,
p=600 mm Hg
Weight of solute, w=2−175g
Weight of benzene, W=39.08g
The molecular weight of benzene,
M=78g
The molecular weight of solute, m=?
According to Raoult's law
p
o
p
o
−p
=
m×W
w×M
640
640−600
=
m×39.08
2.175×78
640
40
=
m×39.08
2.175×78
m=
39.08
16×2.175×78
m=69.60
Hence, the correct option is C
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