Question

two liquids a and b are at temperature 32 degree c .when their equal masses are mixed then the temperature of the mixture is found to be 28 degree c.Their specific heats are in the ratio of​

Answer 1

1 : 1

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Let specific heats of A and B be Ca and Cb respectively.

Let specific heats of A and B be Ca and Cb respectively.Also there masses are m and final temperature T = 28⁰C

Let specific heats of A and B be Ca and Cb respectively.Also there masses are m and final temperature T = 28⁰CHeat released by A=heat absorbed by B

Let specific heats of A and B be Ca and Cb respectively.Also there masses are m and final temperature T = 28⁰CHeat released by A=heat absorbed by B===> mCa ( 32 - T ) = mCb ( T - 24 )

$= = = > \frac{ca}{ca} = \frac{4}{4} = 1$

Thus required ratio is 1 : 1