Question

Two liquids are mixed in the proportion of 3:2 and the mixture is sold at $11 per litre at a 10% profit. If the first liquid costs $2 more per litre than the second, what does it cost per litre

Answer 1

Answer: 1st liquid cost 6$ ,2nd liquid cost 4$

Step-by-step explanation:

110---->11$

100----->(100*11$)/110=10$

1st+2nd=10$-----------------------------------(1)

2nd+2$+2nd=10$

2nd=(10$-2$)/2

2nd=4$

From (1):

1st+2nd=10$

1st=10$-4$=6$