Two tangents ab and ac are drawn to a circle with centre o such that bac=40.A chord cp is drawn parallel to ba
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step 1 ) make a diagram, after making it correctly you will see that the the point at which tangents are touching the circle , the angle made by tangents is 90 each , sum of angle of quadrilateral is 360-(90+90+40)=140(at centre)
step 2) now OAB is traingle whose two sides are equal make equal angle of 20 degree each.
step 3) now comes angle P which is 70 degree ( angle at major chord is half of its centre) which is equal to PB angle made by parallel.
step 4) therefore angle PBO =90-70=20. Therefore angle PBC is 40
Step-by-step explanation:
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