Question

Two Litre of 1.5 M-NaOH solution is mixed with three Litre of 2 M-NaOH solution and one Litre water is also added to it. The molarity of the final solution is : (

Answer 1

Answer:

1.5 M

Explanation:

total no. of moles = M1V1 + M2V2

= 1.5 * 2 + 3 * 2 = 9 moles

final volume = 2 + 3 + 1 = 6 litres

final molarity = total no. of moles / final volume

= 9 / 6 = 1.5 M

Answer 2

Hola mate

Here is your answer -

total amount (in litres) of the solution=2+3+1=6 L

now,(molarity = no. of moles/volume in litres)...so that,

-> 1.5= no. of moles of NaOH/2L -> n.moles NaOH=3

->2= no. of moles of NaOH/3L -> n.moles NaOH= 6

(water is the solvent so don't need to find its moles)

So that, Now, final molarity of the solution will be,

M = n.moles/V(L)

= 3+6/6

= 9/6

= 1.5

HENCE THE MOLARITY OF THE TOTAL SOLUTION WILL BE 1.5M.