Question

Two litre of a ideal gas at 4 atm expands isothermally at 300 K into
vacuum until its volume become 4 litre. The work done in the process
is
16 L atm
8 L atm
1L atm
Zero​

Answer 1

Answer:

Zero

Explanation: Since there is no external pressure the workdone becomes zero

Answer 2

Answer:

The work done in the process is 0 joules.

Explanation:

• A thermodynamic process known as an isothermal process keeps the system's temperature constant. Because heat is transferred into or out of the system so slowly, thermal equilibrium is preserved.
• In the case of expansion, work is done by the system. And it is calculated as,

                                  $\mathrm{W=-P_{ext}\Delta V}$        (1)

Where,

W=work done in the process

$\mathrm{P_{ext}}$=external pressure acting in the process

ΔV=volume change during the isothermal process

As the gas is expanding is a vacuum that has no pressure, i.e.,

$\mathrm{P_{ext}=0}$

∴ W=0

So, the work done in the process is 0 joules.

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