Question

Two long straight wires carrying currents of 2A and 5A in the same direction
are kept parallel, 10 cm apart from each other. Calculate the force acting
between them and write its nature,​

Answer 1

formula used:

when when two parallel conductors separated by a distance R carrying currents I 1 and I 2

the magnetic field of one will exert a force on each other.

refer to attachment for formula and solution

nature : if current in the wires is same in direction

then force is attractive in nature .

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Answer 2

The force between wire is $\dfrac{F}{l}=2\times 10^{-5}\ N/m$ and the force is attractive in nature.

Explanation:

Given that,

Current in first wire, $I_1=2\ A$

Current in second wire, $I_2=5\ A$

Distance between wires, d = 10 cm = 0.1 m

The force per unit length between wire is given by :

$\dfrac{F}{l}=\dfrac{\mu_oI_1I_2}{2\pi d}$

$\dfrac{F}{l}=\dfrac{4\pi \times 10^{-7}\times 2\times 5}{2\pi \times 0.1}$

$\dfrac{F}{l}=2\times 10^{-5}\ N/m$

Here, the current is flowing in same direction, so the force between them is attractive. Hence, this is the required solution.

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