Biology, asked by rajandeepjawanda, 1 year ago

two masses 2kg and 4 kg are connected at the two ends of a light inextensible string passing over a frictionless Pulley if the masses are released then find the acceleration of the masses and the tension in the string

Answers

Answered by Anonymous
36
\sf{\underline{We\:know\:that:}}

4 kg is heavier than 2 kg.

Since 4 kg is heavier than 2 kg, so it will accelerate down, while 2 kg will accelerate up.

Equation of net force on 4 kg is given as:

\boxed{\sf{4 \times 10 - T = 4a}} {---(1)}

Equation of net force on 2 kg is given as:

\boxed{\sf{T - 2 \times 10 = 2a}} {---(2)}

Now,

\sf{\underline{Adding\:the\:above\:two\:equations:}}

\sf{4 \times 10 - 2 \times 10 = (4 + 2) \times a}

\sf{40 - 20 = 6 \times a}

\sf{20 = 6a}

\sf{\frac{20}{6} = a}

\sf{3.33 = a}

So,

\boxed{\sf{a = 3.33 \: m/s ^{2}}}

\sf{\underline{We\:know\:that:}}

4 kg will accelerate downwards, while 2 kg will accelerate upwards, with acceleration \sf{3.33 \: m/s ^{2}} .

Now,

\sf{\underline{In\:order\:to\:find\:tension\:force:}}

\sf{T - 2 \times 10 = 2 \times 3.33}

\sf{T - 20 = 6.66}

\sf{T = 6.66 + 20}

\boxed{\sf{T = 26.66\:N}}

\sf{\underline{Therefore:}}

The acceleration of the masses is \sf{3.33 \: m/s ^{2}} and the tension in the string is \sf{26.66 \: N}.
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