Two masses are connected by a weightless cord passing over a frictionless pulley (see fig). The tension in the cord connecting the masses will be (g = 10 m/s2)
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Let Tension in the string is T and acceleration of the system is a
100gsin37
o
−T=100a...(1)
T−50gsin53
o
=50a...(2)
∵sin53
o
=4/5,sin37
o
=3/5
60g−T=100a...(3)
and T−40g=50a...(4)
from equation (3) and (4)
20g=150a⇒a=
15
2g
=1.33m/s
2
Explanation:
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