Two masses of 0.4 kg and 0.3 kg are attached to the ends of a light string passing over a smooth
pulley. If the mass of 0.4 kg is 6.3 m above the floor when the system is released from rest, find
how long it takes to reach the floor. Calculate the tension in the string and the velocity with which,
the mass strikes the floor. g = 9.8 m/s2 (3s; 3.36 N; 4.2 m/s)
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Answer:
s=ut+1/2at²
Explanation:
s:6.3m
u:0 m/s
t:?
a:+g
then
6.3=9.8t²/2
9.8t²=12.6
t²
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