Two materials having coefficients of thermal conductivity 3K and K and thickness d and 3d, respectively, are joined to form a slab as shown in the figure. The temperatures of the outer surfaces are θ₂ and θ₁ respectively (θ₂ > θ₁). The temperature at the interface is:
(A) (θ₂ + θ₁)/2
(B) (θ₁/10) + (9θ₂/10)
(C) (θ₁/3) + (2θ₂/3)
(D) (θ₁/6) + (5θ₂/6)
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Hey.!!!!!
option (A) is the correct answer.....
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Option A is the correct answer.........
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