Question

A rocket has to be launched from each in such a way that it never returns. If E is the minimum energy delivered by the rocket launcher, what should be the minimum energy that the launcher should have if the same rocket is to be launched from the surface of the moon? Assume that the density of the earth and the moon are equal and that the earth’s volume is 64 times the volume of the moon.
(A) E/32
(B) E/16
(C) E/64
(D) E/4

Answer 1

Answer:

B

We know escape velocity is

$v = \sqrt{ \frac{2GM}{R} } \\ \\ e \: = \frac{1}{2} m {v}^{2} \\ \implies \: e \: \: \: \: \alpha \: \: \: \: {v}^{2} \\ now \\ {v}^{2} = \frac{2GM}{R} = \:\frac{2G \rho \:R {}^{3} }{R} = 2G \rho \: {R}^{2} \\ \\ \implies \: \: e \: \: \alpha \: \: {R}^{2} \:$

Since volume is 64 times radius will be 4 times and energy will 1/16 th . ( Proportional to square of R )