Question

Two materials X and Y are to be used for making two different Toys. if the ratio by weight of X:Y in the first toy is 6:5 and that in the second is 7:13, how many KG of X material must be needed along with 11 KG of first toy and 20kg of the second so to produce a new toy containing 40% of material Y​

Answer 1

Answer:

Two materials X and Y are to be used for making two different Toys. if the ratio by weight of X:Y in the first toy is 6:5 and that in the second is 7:13, how many KG of X material must be needed along with 11 KG of first toy and 20kg of the second so to produce a new toy containing 40% of material Y

Answer 2

Answer:

4 kg  of X metal must be melted along with 11 kg of the first alloy and 20 kg of the second so as to produce a new alloy containing 40% of metal Y

Step-by-step explanation:

ratio by weight of X : Y in the first alloy is 6 : 5 and that in the second is 7 : 13

First Alloy = 11 kg

X metal = (6/11)*11 = 6 kg

Y metal = (5/11)* 11 = 5 kg

Second Alloy = 20 kg

X metal = (7/20)*20 = 7 kg

Y metal = (13/20)* 20 = 13 kg

Let say K kg of X metal added  

Then Total X metal = 6 + 7 + K = 13 + K  kg

Y metal  = 5 + 13 = 18 kg

Total = 11 + 20 + K = 31 + K  kg

containing 40% of metal Y

=> (18/(31 + K) ) * 100 = 40

=> 180 = 124 + 4K

=> 4K = 56

=> K = 14

14 kg  of X metal must be melted along with 11 kg of the first alloy and 20 kg of the second so as to produce a new alloy containing 40% of metal

Step-by-step explanation: