Two men and 7 boys do a piece of work in 14 days . 3men & 8 boys do a same piece of work in 11 days. Then 8 men & 6boys done this same work in how many days as 3 times as the first.
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Answer:
21 days
Step-by-step explanation:
(2 x 14) men +(7 x 14) boys = (3 x 11) men + (8 x 11) boys
=>5 men= 10 boys => 1man= 2 boys
Therefore, (2 men+ 7 boys) = (2 x 2 +7) boys = 11 boys
( 8 men + 6 boys) = (8 x 2 +6) boys = 22 boys.
Let the required number of days be x.
More boys , Less days (Indirect proportion)
More work , More days (Direct proportion)
Boys22:11Work1 : 3}⋮⋮ 14:x
Therefore, (22 * 1 * x) = (11 * 3 * 14)
=> x = 21
Hence, the required number of days = 21
Hope you Understand!!!!!
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