Two men can do a piece of work in 6 hours and 4 hours respectively.After the first person has worked for 2 hours he is joined by other .By when should the work be completed
Answers
Answered by
63
1st person can do 1 work in 6 hours
In 1 hour he does: 1/6 part of work
2nd person can do the same work in 4 hours
In 1 hour he does: 1/4 part of work.
1st person worked for 2 hours.
In 2 hours he did: 2*1/6 = 1/3 part of work
Work Remaining = 1 - 1/3 = 2/3 work
Now both the persons are working
In 1 hour both do: 1/6 + 1/4 = 2+3/12 = 5/12 work
1 hour== 5/12 work
X hours = 2/3 work
5X/12 = 2/3
X = 1.6 hours...
Hence the work will be completed in another 1.6 hours.
Hope it helps
In 1 hour he does: 1/6 part of work
2nd person can do the same work in 4 hours
In 1 hour he does: 1/4 part of work.
1st person worked for 2 hours.
In 2 hours he did: 2*1/6 = 1/3 part of work
Work Remaining = 1 - 1/3 = 2/3 work
Now both the persons are working
In 1 hour both do: 1/6 + 1/4 = 2+3/12 = 5/12 work
1 hour== 5/12 work
X hours = 2/3 work
5X/12 = 2/3
X = 1.6 hours...
Hence the work will be completed in another 1.6 hours.
Hope it helps
Answered by
16
Answer:
1st person can do 1 work in 6 hours
In 1 hour he does: 1/6 part of work
2nd person can do the same work in 4 hours
In 1 hour he does: 1/4 part of work.
1st person worked for 2 hours.
In 2 hours he did: 2*1/6 = 1/3 part of work
Work Remaining = 1 - 1/3 = 2/3 work
Now both the persons are working
In 1 hour both do: 1/6 + 1/4 = 2+3/12 = 5/12 work
1 hour== 5/12 work
X hours = 2/3 work
5X/12 = 2/3
X = 1.6 hours...
Hence the work will be completed in another 1.6 hours.
Hope it helps
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