two men P and Q are standing on the corners A and B of a square ABCD of side 8m. they start moving along the track with a constant speed 2m/s and 10m/s respectively. P is moving in direction A to B and Q is movig in direction B to C. After what time will they meet for the first time.?
plzz experts.....this ques has already been asked but the answer is wrong...the correct ans is 3sec not 2sec as given in the answer posted by an expert....
Answers
Answered by
10
the above image contains the answer for the question
#mark as brainliest
#mark as brainliest
Attachments:
Answered by
7
Answer:
P and Q will meet after 3 seconds.
Step-by-step explanation:
Given:
ABCD is a square with Side = 8 m
Speed of men P at corner A = 2 m/s
Speed of men Q at corner B = 10 m/s
To find: Time when they meet for the first time when they walk in same direction.
Let us assume that P is at rest and Q walks at speed of ( 10 - 2 ) = 8 m/s. Now Q has to walk from B to C, from C to D, from D to A to reach P. Distance Q covered to reach P = 3 × 8 = 24 m.
Now, P and Q are walking at speed of 2m/s and 10m/s. This condition is same as when P is at rest and Q walks at 8m/s.
Distance Q covered = 3 × 8 = 24 m
Time taken to 24 m = 24/8 = 3 seconds
Therefore, P and Q will meet after 3 seconds.
Similar questions