Question

Two men start together to walk a certain distance at 12kmph and 9kmph respectively the former reaches 30min before the latter what is the distance they walked

Answer 1

Answer:

18Km

Explanation:

x is the distance traveled

Time taken by A = $\frac{x}{12}$

Time taken by B = $\frac{x}{9}$

According to question $T_{a} = T_{b} - 30 min$

and 30 min = $\frac{1}{2}$ Hour

so  $T_{a} = T_{b}$ - $\frac{1}{2}$

final equation

              $\frac{x}{12}$ = $\frac{x}{9}$ -  $\frac{1}{2}$

Solve for x we get x = 18 km