Math, asked by bibhutimarch5685, 1 year ago

Two men undertake to do a piece of work for rs.400. one alone can do it in 6 days, the other in 8 days. with the help of a boy, they finish it in 3 days. the boy's share is

Answers

Answered by tardymanchester
9

Answer:

Share of A = Rs 199.8.

Share of B =  Rs 150.

Share of C = Rs 50.19.

Step-by-step explanation:

Given : Two men undertake to do a piece of work for rs.400. one alone can do it in 6 days, the other in 8 days. with the help of a boy, they finish it in 3 days.

To find : The boy's share is?

Solution :

Let A,B and C be the boys working.

We have given A+B can do work in Rs.400

A alone do work in 6 days.

Earning of A per day is

A=\frac{400}{6}=\frac{200}{3}=66.6

B alone do work in 8 days.

Earning of B per day is

A=\frac{400}{8}=50

So including the condition of C,

(A + B + C )\times 3 = 400

(66.6 + 50 + C )\times 3 = 400

116.6\times 3+3C = 400

349.8+3C = 400

3C =50.2

C =16.73

For 3 days work,

Share of A = 3(66.6) = Rs 199.8.

Share of B = 3(50) = Rs 150.

Share of C = 3(16.73) = Rs 50.19.

Answered by sirwarfare321
0

Answer:

Rs. 50

1/6+1/8+1/x=1/3

42x+3= 48x

3= 6x

1/2=x

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