Math, asked by Abhiram2349, 1 year ago

two men x and y started working for a certain company at similar jobs on january 1 1950. x asked for an initial salary of rs. 300 with an annual increment of rs. 30. y asked for an initial salary of rs. 200 with a rise of rs. 15 every six months. assume that the arrangements remained unaltered till december 31 1959. salary is paid on the last day of the month. what is the total amount paid to them as salary during the period?

Answers

Answered by Anonymous
6
(X) the period is 10 years; x1=300 for the first year, +30 for each of the next 9 years. x10=300+9*30=300+270=570. The sum=[300+570]*10/2=4350

(Y) the period is 20 half-years; y1=200 for the first half-year; y20=200+19*15=200+285=485; the sum=[200+485]*20/2=6850

the total is 11200. no such options.
I have assumed that 200 and 300 are yearly salaries. Let's make them monthly ones.

(X) x1=3600; x10=3600+270=3870; the sum=[3600+3870]*10/2=37350
(Y) y1=2400; y20=2400+285=2685; the sum=[2400+2685]*20/2=50850
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