Question

TWO METALLIC SPHERE OF RADII 9 CM AND 10 CM ARE MELTED AND RECAST TO MAKE TWO NEW SPHERES. IF THE RADIUS OF ONE OF THE NEW SPHERE IS 12 CM,THE RADIUS OF THE OTHER NEW SPHERE IS​

Answer 1

Answer:

volume will be conserved

initial volume=4/3π(10^3+9^3)

final volume=4/3π(12^3+x^3)

x=1cm

Answer 2

The Other New Sphere is 1cm.

Step-by-step explanation:

Let, R = 9cm

r= 10cm

and radius of first new sphere be x

and that of second be y

4/3π R^3 + 4/3πr^3 = 4/3πx^3 + 4/3πy^3

➪ 4/3π (R^3 + r^3) = 4/3π(x^3+y^3)

➪ R^3+ r^3= x^3 +y^3

➪ 729 + 1000 = 1728 +y^3

➪ 1729 = 1728 + y^3

➪ 1729 -1728 = y^3

➪ 1 = y^3

➪ 1^3 =y^3

➪ y = 1 ANSWER

Thus radius of second new sphere is 1cm.

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