Two metallic wires A and B are made using copper .The raduis of wire A is r while its length is l.A dc voltage Vis applied across the wire A causing power dissipation ,P.the raduis of B is 2r and its length is 2l and the same dc voltage V IS appilled across is it causing power dissipation P1.
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Explanation:
Metallic wires = A and B
Radius = r Length = l
Resistance of A = l/πr²
Resistance of B = 2l/π(2r)²
= 2l/4πr²
Resistance in parallel
1/R = 1/(l/πr²) + 1/(2l/4πr²)
1/R = πr²/l + 4πr²/2l
1/R = πr²/l + 2πr²/l
1/R = 3πr²/l
R = l/3πr²
Resistance A = A parallel combination resistance
= l/πr² ÷ l/3πr²
= l/πr² x 3πr²/l
= 3/1
Thus the ratio is 3 : 1 .
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