Question

Two metals X and Y form the salts XSO4 and Y2SO4, respectively. The solution of salt XSO4 is blue in colour whereas that of Y2SO4 is colourless. When barium chloride solution is added to XSO4 solution, then a white precipitate Z is formed alongwith a salt which turns the solution green. And when barium chloride solution is added to Y2SO4 solution, then the same white precipitate Z is formed alongwith colourless common salt solution.
(a) What could the metals X and Y be?
(b) Write the name and formula of salt XSO4.
(c) Write the name and formula of salt Y2SO4.
(d) What is the name and formula of white precipitate Z?
(e) Write the name and formula of the salt which turns the solution green in the first case.

Answer 1

(a) The metal X is copper and metal Y is sodium.

(b) The name of the salt $CuSO_4 (XSO_4)$ is copper sulphate.

(c) The name of the salt $Na_2SO_4 (Y_2SO_4)$ is sodium sulphate.

(d) The precipitate Z formed while reacting with $CuSO_4 (XSO_4)$ is barium sulphate $(BaSO_4)$.

(e) The name of the salt that turn green colour is copper chloride and its formula is $CuCl_2$.

Explanation:

• Copper is a reddish brown metal. It is a soft and very reactive metal (corrosive in nature). It is a very good conductor of heat and electricity.
• Copper sulphate is a blue coloured compound. It is used in fungicides and used in dyes for its colour.
• Sodium is a silvery white alkali metal. It is a highly reactive metal. It is used in manufacturing soaps and as de-icing agent.
• Sodium sulphate is a white salt highly dissolvable in water. It is used in the manufacturing of detergents and processing of paper pulp.
• Barium sulphate is a white crystalline and odourless salt. It is used as drilling fluids; white pigment in paints; and in photographic plate.

You can get all the answers of Chapter 1 in the link below:

https://brainly.in/question/13848082

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